In an experiment on double slit interference, the distance separating the slits is 1.0 mm and the wavelength of the light is 5.0 10⁻⁷ m . The screen is placed 1.0 m away from the slits. Evaluate the distance between the centre of the central maximum and the centre of the first minimum.

Step-by-step solution

Given d = 1.0 mm = 10⁻³ m , = 5.0 10⁻⁷ m , and D = 1.0 m . The fringe width is = D d . The distance between the centre of the central maximum and the centre of the first minimum is half of the fringe width, which is 2 = D 2d . Substituting the given values: D 2d = 5.0 10⁻⁷ 1.0 2 10⁻³ = 2.5 10⁻⁴ m = 0.25 mm