During a double slit interference experiment, light with a wavelength of 5.0 10⁻⁷ m is used, and the separation between the slits is 1.0 mm . The screen is positioned 1.0 m from the slits. Determine how many bright fringes are present in a one-centimeter width on the screen.

Step-by-step solution

The fringe width in a double slit experiment is given by = D d Substituting the given values: = 5.0 10⁻⁷ m D = 1.0 m d = 1.0 mm = 1.0 10⁻³ m = 5.0 10⁻⁷ 1.0 1.0 10⁻³ = 5.0 10⁻⁴ m The given width on the screen is W = 1 cm = 1.0 10⁻² m The number of bright fringes in this width is n = W n = 1.0 10⁻² 5.0 10⁻⁴ = 20