In a Young's double slit experiment, two narrow vertical slits positioned 0.800 mm apart are illuminated by the same source of yellow light having a wavelength of 589 nm . Determine the distance between adjacent bright bands in the interference pattern formed on a screen 2.00 m away.

Step-by-step solution

Given, Wavelength of light, = 589 nm = 589 10⁻⁹ m Distance between the slits, d = 0.800 mm = 0.800 10⁻³ m Distance of the screen from the slits, D = 2.00 m The distance between adjacent bright bands is the fringe width, given by the formula: = D d Substituting the given values: = 589 10⁻⁹ 2.00 0.800 10⁻³ = 1178 10⁻⁹ 0.800 10⁻³ = 1472.5 10⁻⁶ m = 1.4725 10⁻³ m 1.47 mm