Concepts Of Physics MCQ Edition [Volume 1]
- Exam
- Concepts Of Physics MCQ Edition [Volume 1]
- Subject
- Physics
- Chapter
- Simple Harmonic Motion
Concepts Of Physics MCQ Edition [Volume 1] · Physics · Simple Harmonic Motion
A simple pendulum of length l is suspended from the ceiling of a...
A simple pendulum of length is suspended from the ceiling of a car travelling with a speed on a circular horizontal road of radius . Determine the time period of small oscillations.
Options
- A2\pi \sqrt{\dfrac{l}{\left( g^2 + \dfrac{v^4}{r^2} \right)^{1/2}}}
- B2\pi \sqrt{\dfrac{l}{\left( g^2 + \dfrac{v^2}{r} \right)^{1/2}}}
- C
- D2\pi \sqrt{\dfrac{l}{\left( g^2 - \dfrac{v^4}{r^2} \right)^{1/2}}}
Correct answer
A. 2\pi \sqrt{\dfrac{l}{\left( g^2 + \dfrac{v^4}{r^2} \right)^{1/2}}}
Step-by-step solution
In the frame of the car, the pendulum bob experiences a pseudo force (centrifugal force) in the horizontal direction due to the circular motion of the car.
The centrifugal acceleration is directed radially outward.
The acceleration due to gravity acts vertically downward.
Since the horizontal and vertical accelerations are perpendicular to each other, the effective acceleration due to gravity is given by:
The time period of small oscillations of a simple pendulum is given by:
Substituting the value of , we get:
$T = 2\pi \sqrt{\dfrac{l}{\left( g^2 + \dfrac{v^4}{r^2} \right)^{1/2}}}
The centrifugal acceleration is directed radially outward.
The acceleration due to gravity acts vertically downward.
Since the horizontal and vertical accelerations are perpendicular to each other, the effective acceleration due to gravity is given by:
The time period of small oscillations of a simple pendulum is given by:
Substituting the value of , we get:
$T = 2\pi \sqrt{\dfrac{l}{\left( g^2 + \dfrac{v^4}{r^2} \right)^{1/2}}}