As illustrated in the figure, a lady wears an ear-ring suspended by a light wire of length 3 cm . Determine the time period of small oscillations of the ear-ring when the lady is standing on the ground.

Step-by-step solution

The ear-ring suspended by a light wire can be considered as a simple pendulum. The time period T of small oscillations for a simple pendulum is given by: T = 2 L g Given: Length of the wire, L = 3 cm = 0.03 m Acceleration due to gravity, g 10 m/s ^2 Substituting the values into the formula: T = 2 0.03 10 T = 2 3.14 0.003 T 6.28 0.0547 T 0.34 s