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Concepts Of Physics MCQ Edition [Volume 1]PhysicsSimple Harmonic Motion

A particle is subjected to two simple harmonic motions of the same time period in the same direction. The amplitude of the first motion is 3.0 cm while that of the second is 4.0 cm . Determine the resultant amplitude if the phase difference between the motions is 0^ .

Options

  1. A1.0 cm
  2. B7.0 cm
  3. C6.1 cm
  4. D5.0 cm

Correct answer

B. 7.0 cm

Step-by-step solution

The resultant amplitude A of two simple harmonic motions in the same direction is given by A = A₁^2 + A₂^2 + 2A₁A₂ Given A₁ = 3.0 cm , A₂ = 4.0 cm , and phase difference = 0^ . Substituting the values: A = 3.0^2 + 4.0^2 + 2(3.0)(4.0) 0^ A = 9.0 + 16.0 + 24.0(1) A = 49.0 = 7.0 cm

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