Concepts Of Physics MCQ Edition [Volume 1]PhysicsSimple Harmonic Motion
A particle undergoes two simple harmonic motions, one along the X-axis and the other along a line at an angle of 45^ to the X-axis. These motions are described by x = x₀ t and s = s₀ t . Determine the amplitude of the resultant motion.
Options
- A[ x₀^2 + s₀^2 + x₀ s₀ ]^ 1/2
- B[ x₀^2 + s₀^2 + 2 , x₀ s₀ ]^ 1/2
- C[ x₀^2 + s₀^2 + x₀ s₀ 2 ]^ 1/2
- D[ x₀^2 + s₀^2 - 2 , x₀ s₀ ]^ 1/2
Correct answer
B. [ x₀^2 + s₀^2 + 2 , x₀ s₀ ]^ 1/2
Step-by-step solution
The two simple harmonic motions are given by x = x₀ t , i and s = s₀ t ( 45^ i + 45^ j ) . Since both simple harmonic motions are in the same phase, the resultant amplitude is the vector sum of their individual amplitudes. The angle between the two amplitude vectors is = 45^ . Using the vector addition formula, the resultant amplitude A is given by: A = x₀^2 + s₀^2 + 2 x₀ s₀ 45^ A = x₀^2 + s₀^2 + 2 x₀ s₀ ( 1 2 ) A = [ x₀^2 + s₀^2 + 2 x₀ s₀ ]^ 1/2