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JEE Main 202628 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2026 · 28 January · Morning Shift · Chemistry · Hydrocarbons

Ph- CH=CH _ 2 [HBr] (PhCOO)_ 2 Product Consider the above reaction...

Ph−\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}2→HBr(PhCOO)2_{2} \xrightarrow[\mathrm{HBr}]{(\mathrm{PhCOO})_{2}} Product
Consider the above reaction
A. The reaction proceeds through a more stable radical intermediate.
B. The role of peroxide is to generate H∘\mathrm{H}^{\circ} (Hydrogen radical).
C. During this reaction, benzene is formed as a byproduct.
D. 1-Bromo-2-phenylethane is formed as the minor product.
E. The same reaction in absence of peroxide proceeds via carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:Ph- CH=CH _ 2 [HBr] (PhCOO)_ 2 Product Consider the above reaction A. The reaction proceeds through a more stable

Options

  1. AC, D & E Only
  2. BA, B & D Only
  3. CA, C & E Only
  4. DA & E Only

Correct answer

C. A, C & E Only

Step-by-step solution

Ph−CH=CH2→HBr(PhCOO)2Ph−CH2−CH2−BrPh-CH=CH_2 \xrightarrow[HBr]{(PhCOO)_2} Ph-CH_2-CH_2-Br
Anti Markovnikov addition
• Reaction follow radical addition in presence of peroxide
• In absence of peroxide follow carbocation mechanism
• Benzene also formed
Ph- CH=CH _ 2 [HBr] (PhCOO)_ 2 Product Consider the above reaction A. The reaction proceeds through a more stable
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