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Ph - CH = CH ₂ [ HBr ] ( PhCOO )₂ Product Consider the above reaction A. The reaction proceeds through a more stable radical intermediate. B. The role of peroxide is to generate H ^ (Hydrogen radical). C. During this reaction, benzene is formed as a byproduct. D. 1-Bromo-2-phenylethane is formed as the minor product. E. The same reaction in absence of peroxide proceeds via carbocation intermediate. Identify the corre

Options

  1. AC, D & E Only
  2. BA, B & D Only
  3. CA, C & E Only
  4. DA & E Only

Correct answer

C. A, C & E Only

Step-by-step solution

Ph-CH=CH₂ [HBr] (PhCOO)₂ Ph-CH₂-CH₂-Br Anti Markovnikov addition • Reaction follow radical addition in presence of peroxide • In absence of peroxide follow carbocation mechanism • Benzene also formed

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