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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

Two sources of sound S_1 and S_2 vibrate at the same frequency and...

Two sources of sound S1S_1 and S2S_2 vibrate at the same frequency and are in phase as shown in the figure. The intensity of sound detected at point PP is I0I_0 when both sources are active. If one source is switched off, what will be the intensity at PP? Consider (a) θ=45∘\theta = 45^\circ and (b) θ=60∘\theta = 60^\circ.
Two sources of sound S_1 and S_2 vibrate at the same frequency and are in phase as shown in the figure. The intensity

Options

  1. AI04\dfrac{I_0}{4}
  2. BI02\dfrac{I_0}{2}
  3. CI0I_0
  4. D2I02I_0

Correct answer

A. I04\dfrac{I_0}{4}

Step-by-step solution

From the given figure, point PP lies on the perpendicular bisector of S1S2S_1S_2, so the path difference is zero (Δx=0\Delta x = 0).

Let the intensity of each individual source at PP be I′I'.

Since the sources are in phase and the path difference is zero, they interfere constructively. The resultant intensity is:

I0=I′+I′+2I′I′cos⁡0∘=4I′I_0 = I' + I' + 2\sqrt{I' I'} \cos 0^\circ = 4I'

If one source is switched off, the intensity at PP is solely due to the single remaining source, which is I′I'.

New intensity =I′=I04= I' = \dfrac{I_0}{4}

This result depends only on the path difference being zero and is completely independent of the angle θ\theta.
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