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JEE Main 202622 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
22 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2026 · 22 January · Morning Shift · Chemistry · Hydrocarbons

Given below are two statements: Statement I : Benzene is nitrated...

Given below are two statements:
Statement I: Benzene is nitrated to give nitrobenzene, which on further treatment with CH3COCl/AlCl3\mathrm{CH}_{3} \mathrm{COCl} / \mathrm{AlCl}_{3} will give
Given below are two statements: Statement I : Benzene is nitrated to give nitrobenzene, which on further treatment with
Statement II: −NO2-\mathrm{NO}_{2} group is a mm-directing, and deactivating group.
In the light of the above statements, choose the most appropriate answer from the options given below

Options

  1. AStatement I is incorrect but Statement II is correct
  2. BBoth Statement I and Statement II are incorrect
  3. CBoth Statement I and Statement II are correct
  4. DStatement I is correct but Statement II is incorrect

Correct answer

A. Statement I is incorrect but Statement II is correct

Step-by-step solution

Statement I: Benzene reacts with nitrating mixture (conc.HNO3+conc.H2SO4conc. HNO_3 + conc. H_2SO_4) to form nitrobenzene. However, nitrobenzene is highly deactivated due to the strong electron-withdrawing −I-I and −M-M effects of the −NO2-NO_2 group. Friedel-Crafts reactions (alkylation or acylation) do not occur on strongly deactivated rings like nitrobenzene. Thus, nitrobenzene will not react with CH3COCl/AlCl3CH_3COCl/AlCl_3 to give m-nitroacetophenone. Statement I is incorrect.

Statement II: The −NO2-NO_2 group is a meta-directing group because it withdraws electron density from the ortho and para positions more than from the meta position. It is also a deactivating group as it reduces the overall electron density of the benzene ring, making it less reactive towards electrophilic aromatic substitution. Statement II is correct.

Therefore, Statement I is incorrect but Statement II is correct.
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