JEE Main 202622 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Hydrocarbons
JEE Main 2026 · 22 January · Morning Shift · Chemistry · Hydrocarbons
The cycloalkene (X) on bromination consumes one mole of bromine per...
The cycloalkene on bromination consumes one mole of bromine per mole of and gives the product in which ratio is 3:1. The percentage of bromine in the product is %. (Nearest integer) (Given : molar mass in )
Correct answer
0
Step-by-step solution
A cycloalkene (X) undergoes bromination with 1 mole of Br₂, consuming 2 moles of Br atoms (addition to the double bond).
The product (Y) has C:Br ratio of 3:1.
With 2 Br atoms present, the number of C atoms is 2 × 3 = 6.
Therefore, product Y has composition C₆H₁₂Br₂ with molar mass
g/mol.
Percentage of Br = (2 × 80 / 244) × 100 = (160 / 244) × 100
= 65.57%, which rounds to 66% (nearest integer).
The product (Y) has C:Br ratio of 3:1.
With 2 Br atoms present, the number of C atoms is 2 × 3 = 6.
Therefore, product Y has composition C₆H₁₂Br₂ with molar mass
g/mol.
Percentage of Br = (2 × 80 / 244) × 100 = (160 / 244) × 100
= 65.57%, which rounds to 66% (nearest integer).