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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Wave Motion and Waves on a String

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Wave Motion and Waves on a String

A wave pulse travelling on a string at a speed of 40 cm s^ -1 in...

A wave pulse travelling on a string at a speed of 40 cm s−140 \text{ cm s}^{-1} in the negative xx-direction has its maximum located at x=0x = 0 when t=0t = 0. Where will this maximum be found at t=5 st = 5 \text{ s}?

Options

  1. Ax=−8 mx = -8 \text{ m}
  2. Bx=2 mx = 2 \text{ m}
  3. Cx=−20 mx = -20 \text{ m}
  4. Dx=−2 mx = -2 \text{ m}

Correct answer

D. x=−2 mx = -2 \text{ m}

Step-by-step solution

Given speed of the wave pulse, v=40 cm s−1=0.4 m s−1v = 40 \text{ cm s}^{-1} = 0.4 \text{ m s}^{-1}.

Since the wave is travelling in the negative xx-direction, the position of the maximum at time tt is given by x=−vtx = -vt.

Substituting the values for t=5 st = 5 \text{ s}:

x=−(0.4 m s−1)×5 s=−2 mx = - (0.4 \text{ m s}^{-1}) \times 5 \text{ s} = -2 \text{ m}.
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