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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Wave Motion and Waves on a String

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Wave Motion and Waves on a String

The figure displays a wave pulse at t = 0 . The pulse travels to...

The figure displays a wave pulse at t=0t = 0. The pulse travels to the right with a speed of 10 cm s−110 \text{ cm s}^{-1}. Determine the respective rightward shifts of the shape of the string at t=1 st = 1 \text{ s}, 2 s2 \text{ s} and 3 s3 \text{ s}.
The figure displays a wave pulse at t = 0 . The pulse travels to the right with a speed of 10 cm s^ -1 . Determine the

Options

  1. A5 cm5 \text{ cm}, 10 cm10 \text{ cm}, and 15 cm15 \text{ cm}
  2. B10 cm10 \text{ cm}, 20 cm20 \text{ cm}, and 30 cm30 \text{ cm}
  3. C20 cm20 \text{ cm}, 40 cm40 \text{ cm}, and 60 cm60 \text{ cm}
  4. D1 cm1 \text{ cm}, 2 cm2 \text{ cm}, and 3 cm3 \text{ cm}

Correct answer

B. 10 cm10 \text{ cm}, 20 cm20 \text{ cm}, and 30 cm30 \text{ cm}

Step-by-step solution

The speed of the wave pulse is given as v=10 cm s−1v = 10 \text{ cm s}^{-1}.

The rightward shift of the wave pulse in time tt is the distance traveled by it, which is given by d=v×td = v \times t.

At t=1 st = 1 \text{ s}, the shift is d1=10 cm s−1×1 s=10 cmd_1 = 10 \text{ cm s}^{-1} \times 1 \text{ s} = 10 \text{ cm}.

At t=2 st = 2 \text{ s}, the shift is d2=10 cm s−1×2 s=20 cmd_2 = 10 \text{ cm s}^{-1} \times 2 \text{ s} = 20 \text{ cm}.

At t=3 st = 3 \text{ s}, the shift is d3=10 cm s−1×3 s=30 cmd_3 = 10 \text{ cm s}^{-1} \times 3 \text{ s} = 30 \text{ cm}.

Therefore, the respective rightward shifts are 10 cm10 \text{ cm}, 20 cm20 \text{ cm}, and 30 cm30 \text{ cm}.
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