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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Wave Motion and Waves on a String

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Wave Motion and Waves on a String

A wave travelling on a string stretched along the X -axis has an...

A wave travelling on a string stretched along the XX-axis has an equation given by y=A e−(xa+tT)2y = A\, e^{-\left(\dfrac{x}{a} + \dfrac{t}{T}\right)^2}. Determine the dimensions of AA, aa, and TT.

Options

  1. ALL, L−1L^{-1}, T−1T^{-1}
  2. BL−1L^{-1}, LL, TT
  3. CLL, TT, LL
  4. DLL, LL, TT

Correct answer

D. LL, LL, TT

Step-by-step solution

The argument of the exponential function must be dimensionless. Therefore, the terms xaand\dfrac{x}{a} and\dfrac{t}{T}aredimensionless.<br><br>Sinceare dimensionless.<br><br>Sincexrepresentsposition,itsdimensionisrepresents position, its dimension isL.For. For\dfrac{x}{a}tobedimensionless,thedimensionofto be dimensionless, the dimension ofamustbemust beL.<br><br>Since.<br><br>Sincetrepresentstime,itsdimensionisrepresents time, its dimension isT.For. For\dfrac{t}{T}tobedimensionless,thedimensionofto be dimensionless, the dimension ofTmustbemust beT.<br><br>Theexponentialterm.<br><br>The exponential terme^{-\left(\dfrac{x}{a} + \dfrac{t}{T}\right)^2} is a dimensionless quantity. Therefore, the dimension of AA must be the same as the dimension of yy.

Since yy represents the displacement of the wave, its dimension is LL. Thus, the dimension of AA is LL.

The dimensions of AA, aa, and TT are LL, LL, and TT respectively.
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