Determine the average force required to accelerate a 500 kg car from rest to 72 km/h over a distance of 25 m .

Correct answer: A. 4000 N Given mass of the car, m = 500 kg Initial velocity, u = 0 Final velocity, v = 72 km/h = 72 × (5)/(18) m/s = 20 m/s Distance covered, s = 25 m Using the equation of motion v^2 = u^2 + 2as : (20)^2 = 0 + 2a(25) 400 = 50a a = 8 m/s^2 The average force required is given by Newton's second law: F = ma F = 500 × 8 = 4000 N

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Work and Energy

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Work and Energy

Determine the average force required to accelerate a 500 kg car...

Determine the average force required to accelerate a

500 \text{ kg}

car from rest to

72 \text{ km/h}

over a distance of

25 \text{ m}

Options

A $4000 \text{ N}$
B $400 \text{ N}$
C $8000 \text{ N}$
D $51840 \text{ N}$

Correct answer

A. $4000 \text{ N}$

Step-by-step solution

Given mass of the car,

m = 500 \text{ kg}

Initial velocity,

u = 0

Final velocity,

v = 72 \text{ km/h} = 72 \times \dfrac{5}{18} \text{ m/s} = 20 \text{ m/s}

Distance covered,

s = 25 \text{ m}

Using the equation of motion

v^2 = u^2 + 2as

(20)^2 = 0 + 2a(25)

400 = 50a

a = 8 \text{ m/s}^2

The average force required is given by Newton's second law:

F = ma

F = 500 \times 8 = 4000 \text{ N}

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