Determine the average force required to accelerate a 500 kg car from rest to 72 km/h over a distance of 25 m .

Step-by-step solution

Given mass of the car, m = 500 kg Initial velocity, u = 0 Final velocity, v = 72 km/h = 72 5 18 m/s = 20 m/s Distance covered, s = 25 m Using the equation of motion v^2 = u^2 + 2as : (20)^2 = 0 + 2a(25) 400 = 50a a = 8 m/s ^2 The average force required is given by Newton's second law: F = ma F = 500 8 = 4000 N