A car travels at a constant speed along a road, as shown in the...

At the highest point of a convex path, the net force towards the center of curvature provides the necessary centripetal force.

The equation of motion is:
$mg - N = \dfrac{mv^2}{R}$

Rearranging for the normal force $N$, we get:
$N = mg - \dfrac{mv^2}{R}$

From the given figure, the curve at point A is sharper than the curve at point B. This means the radius of curvature at A is smaller than that at B, i.e., $R_A < R_B$.

Since the car travels at a constant speed $v$, the term $\dfrac{mv^2}{R}$ is larger for point A than for point B.

Therefore, $\dfrac{mv^2}{R_A} > \dfrac{mv^2}{R_B}$

$\Rightarrow mg - \dfrac{mv^2}{R_A} < mg - \dfrac{mv^2}{R_B}$

$\Rightarrow N_A < N_B$