A car travels at a constant speed along a road, as shown in the figure. The normal force exerted by the road on the car is N_A when the car is at point A , and N_B when it is at point B .

Step-by-step solution

At the highest point of a convex path, the net force towards the center of curvature provides the necessary centripetal force. The equation of motion is: mg - N = mv^2 R Rearranging for the normal force N , we get: N = mg - mv^2 R From the given figure, the curve at point A is sharper than the curve at point B. This means the radius of curvature at A is smaller than that at B, i.e., R_A Since the car travels at a constant speed v , the term mv^2 R is larger for point A than for point B. Therefore, mv^2 R_A > mv^2 R