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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Light Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Light Waves

Two coherent sources with different intensities emit waves that...

Two coherent sources with different intensities emit waves that interfere with each other. If the ratio of the maximum intensity to the minimum intensity is 2525, the ratio of the intensities of the two sources is

Options

  1. A9:49 : 4
  2. B625:1625 : 1
  3. C5:15 : 1
  4. D25:125 : 1

Correct answer

A. 9:49 : 4

Step-by-step solution

Let the intensities of the two coherent sources be I1I_1 and I2I_2.

The maximum intensity in the interference pattern is given by I_\max = (\sqrt{I_1} + \sqrt{I_2})^2

The minimum intensity is given by I_\min = (\sqrt{I_1} - \sqrt{I_2})^2

Given that the ratio of maximum to minimum intensity is 2525:

\dfrac{I_\max}{I_\min} = \dfrac{(\sqrt{I_1} + \sqrt{I_2})^2}{(\sqrt{I_1} - \sqrt{I_2})^2} = 25

Taking the square root on both sides:

I1+I2I1−I2=5\dfrac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sqrt{I_2}} = 5

I1+I2=5I1−5I2\sqrt{I_1} + \sqrt{I_2} = 5\sqrt{I_1} - 5\sqrt{I_2}

6I2=4I16\sqrt{I_2} = 4\sqrt{I_1}

I1I2=64=32\dfrac{\sqrt{I_1}}{\sqrt{I_2}} = \dfrac{6}{4} = \dfrac{3}{2}

Squaring both sides, the ratio of the intensities is:

I1I2=94\dfrac{I_1}{I_2} = \dfrac{9}{4}
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