Concepts Of Physics MCQ Edition [Volume 1]
- Exam
- Concepts Of Physics MCQ Edition [Volume 1]
- Subject
- Physics
- Chapter
- Optical Instruments
Concepts Of Physics MCQ Edition [Volume 1] · Physics · Optical Instruments
When an object is positioned at a distance u from a simple...
When an object is positioned at a distance from a simple microscope having a focal length , the resulting angular magnification depends
Options
- Aon both and
- Bon neither nor
- Con but not on
- Don but not on
Correct answer
D. on but not on
Step-by-step solution
The angular magnification of a simple microscope is defined as the ratio of the angle subtended by the image at the eye () to the angle subtended by the object at the unaided eye when placed at the least distance of distinct vision ().
Assuming the eye is close to the lens, the angle subtended by the image is . Using the linear magnification formula \left(\dfrac{v}{u}\right), we get \dfrac{h(v/u)}{v} = \dfrac{h}{u}.
The angle subtended by the object at the unaided eye is \dfrac{h}{D}.
Therefore, the angular magnification is \dfrac{\theta_i}{\theta_o} = \dfrac{h/u}{h/D} = \dfrac{D}{u}.
Thus, for a given object distance , the angular magnification depends only on (and the constant ), and is independent of the focal length .
Assuming the eye is close to the lens, the angle subtended by the image is . Using the linear magnification formula \left(\dfrac{v}{u}\right), we get \dfrac{h(v/u)}{v} = \dfrac{h}{u}.
The angle subtended by the object at the unaided eye is \dfrac{h}{D}.
Therefore, the angular magnification is \dfrac{\theta_i}{\theta_o} = \dfrac{h/u}{h/D} = \dfrac{D}{u}.
Thus, for a given object distance , the angular magnification depends only on (and the constant ), and is independent of the focal length .