At t = 0 , a particle has a velocity u towards east. Its acceleration is constant and directed towards west. Let x_A and x_B denote the magnitude of displacements in the first 10 seconds and the subsequent 10 seconds, respectively.

Step-by-step solution

Let the initial velocity be u towards east and the constant acceleration be a towards west. Taking east as the positive direction, the velocity is u and acceleration is -a . The displacement of the particle at time t is given by s = ut - 1 2 at^2 . The magnitude of displacement in the first 10 seconds is: x_A = |s(10) - s(0)| = |10u - 50a| The magnitude of displacement in the subsequent 10 seconds is: x_B = |s(20) - s(10)| = |(20u - 200a) - (10u - 50a)| = |10u - 150a| Comparing x_A and x_B for different values of u