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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A person travelling along a straight line moves with a uniform...

A person travelling along a straight line moves with a uniform velocity v1v_1 for a certain duration and with a uniform velocity v2v_2 for the next equal duration. The average velocity vv is given by

Options

  1. Av=v1+v22v = \dfrac{v_1 + v_2}{2}
  2. B1v=1v1+1v2\dfrac{1}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2}
  3. Cv=v1v2v = \sqrt{v_1 v_2}
  4. D2v=1v1+1v2\dfrac{2}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2}

Correct answer

A. v=v1+v22v = \dfrac{v_1 + v_2}{2}

Step-by-step solution

Let the equal time intervals be tt.

Distance travelled in the first interval is d1=v1td_1 = v_1 t.

Distance travelled in the second interval is d2=v2td_2 = v_2 t.

Total distance travelled is d=d1+d2=v1t+v2t=(v1+v2)td = d_1 + d_2 = v_1 t + v_2 t = (v_1 + v_2) t.

Total time taken is T=t+t=2tT = t + t = 2t.

Average velocity v=Total distanceTotal time=(v1+v2)t2t=v1+v22v = \dfrac{\text{Total distance}}{\text{Total time}} = \dfrac{(v_1 + v_2) t}{2t} = \dfrac{v_1 + v_2}{2}.
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