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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A person moving along a straight line travels with a uniform...

A person moving along a straight line travels with a uniform velocity v1v_1 for a distance xx, and then with a uniform velocity v2v_2 for the next equal distance. The average velocity vv is given by

Options

  1. A2v=1v1+1v2\dfrac{2}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2}
  2. B1v=1v1+1v2\dfrac{1}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2}
  3. Cv=v1+v22v = \dfrac{v_1 + v_2}{2}
  4. Dv=v1v2v = \sqrt{v_1 v_2}

Correct answer

A. 2v=1v1+1v2\dfrac{2}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2}

Step-by-step solution

Time taken to travel the first distance xx is t1=xv1t_1 = \dfrac{x}{v_1}

Time taken to travel the next distance xx is t2=xv2t_2 = \dfrac{x}{v_2}

Total distance traveled is x+x=2xx + x = 2x

Total time taken is t=t1+t2=xv1+xv2t = t_1 + t_2 = \dfrac{x}{v_1} + \dfrac{x}{v_2}

Average velocity v=Total distanceTotal time=2xxv1+xv2v = \dfrac{\text{Total distance}}{\text{Total time}} = \dfrac{2x}{\dfrac{x}{v_1} + \dfrac{x}{v_2}}

v=21v1+1v2v = \dfrac{2}{\dfrac{1}{v_1} + \dfrac{1}{v_2}}

2v=1v1+1v2\dfrac{2}{v} = \dfrac{1}{v_1} + \dfrac{1}{v_2}
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