Product A and B formed in the following set of reactions are:

The reaction is known as hydroboration-oxidation. In this reaction, ${B}_{2}{H}_{6}$ adds to the double bond of propene, resulting in the formation of an organoborane intermediate. Subsequent treatment with ${H}_{2}{O}_{2}$ converts the organoborane intermediate to an alcohol. Hydration follows anti-Markownikoff's rule.

In this hydration reaction, 1-methylcyclohexene (an alkene) is reacted with aqueous ${H}_{3}{O}^{+}$ (formed from water and a strong acid such as ${H}_{2}{SO}_{4}$), resulting in Markovnikov addition of water across the pi bond. The product is an alcohol.