JEE Main202430 Jan 2024Morning ShiftChemistryHydrocarbonsActual
Compound A formed in the following reaction reacts with B gives the product C . Find out A and B .
Options
- AA = CH 3 - C ≡ C - Na + , B = CH 3 - CH 2 - CH 2 - Br
- BA = CH 3 - CH = CH 2 , B = CH 3 - CH 2 - CH 2 - Br
- CA = CH 3 - CH 2 - CH 3 , B = CH 3 - C ≡ CH
- DA = CH 3 - C ≡ C - Na + , B = CH 3 - CH 2 - CH 3
Correct answer
A. A = CH 3 - C ≡ C - Na + , B = CH 3 - CH 2 - CH 2 - Br
Step-by-step solution
When CH 3 C ≡ CH reacts with sodium an intermediate CH 3 C ≡ CNa is formed which on further reaction with propyl bromide gives CH 3 CH 2 CH 2 C ≡ CCH 3 as the product. The second step of the reaction follows, S N 2 mechanism. The reaction is as follows, Hence in the above reaction, A = CH 3 - C ≡ C - Na + , B = CH 3 - CH 2 - CH 2 - Br Hence option A is the answer.