A solid is floating in a liquid in a partially dipped state.

For a solid floating in a liquid, the system is in equilibrium. The upward buoyant force exerted by the liquid on the solid balances the downward weight of the solid. Hence, the buoyant force equals the weight of the solid.

According to Newton's third law of motion, the solid exerts an equal and opposite force on the liquid. Since the buoyant force equals the weight of the solid, the solid exerts a downward force on the liquid equal to its weight.

According to Archimedes' principle, the buoyant force is equal to the weight of the displaced liquid. Therefore, the weight of the displaced liquid is equal to the total weight of the solid.

The weight of the submerged part of the solid is $V_{sub} \rho_s g$, while the weight of the displaced liquid is $V_{sub} \rho_l g$. Since the solid is partially dipped, $\rho_s < \rho_l$, meaning the weight of the submerged part is strictly less than the weight of the displaced liquid.