When 0 . 01 mol of an organic compound containing 60 % carbon was burnt completely, 4 . 4 g of CO 2 was produced. The molar mass of compound is _____ gmol - 1 (Nearest integer)

Step-by-step solution

Let M is the molar mass of the compound g / mol mass of compound = mole   ×   molecular   mass   =   0 . 01 M   g mass of carbon = 0 . 01 M × 60 100 ....(i) moles of carbon = mass   of   compound molecular   mass   of   carbon   =   0 . 01 M 12 × 60 100 ....(ii) Thus, moles of CO 2 from combustion = 4 . 4 44 = 0.1 moles of carbon dioxide Using POAC, Thus, from (i) and (ii), ⇒ 0 . 01 M 12 × 60 100 = 4 . 4 44 ⇒ M = 4 . 4