17mg of a hydrocarbon (M.F. C _ 10 H _ 16 ) takes up 8 . 40mL of the H _ 2 gas measured at 0 ° C and 760mm of Hg . Ozonolysis of the same hydrocarbon yields CH _ 3 - C _ | | _ O - CH _ 3 , H - C _ | | _ O - H, H - C _ |

Question

Quantrex Academy · Accepted Answer

Correct answer: 3

From the given information:
Moles of hydrocarbon $= \dfrac{17 \times {10}^{- 3}}{136} = 1 . 25 \times {10}^{- 4}$ Mole of ${H}_{2}$ gas

$⇒ 1 \times \dfrac{8 . 40}{1000} = n \times 0 . 0821 \times 273$

$⇒ n = 3 . 75 \times {10}^{- 4}$

Thus, moles of hydrogen used to hydrogenate double bonds:

$= \dfrac{3 . 75 \times {10}^{- 4}}{1 . 25 \times {10}^{- 4}} = 3$

17mg of a hydrocarbon (M.F. C _ 10 H _ 16 ) takes up 8 . 40mL of...

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