17 mg of a hydrocarbon (M.F. C 10 H 16 ) takes up 8 . 40 mL of the H 2 gas measured at 0 ° C and 760 mm of Hg . Ozonolysis of the same hydrocarbon yields CH 3 - C | | O - CH 3 , H - C | | O - H , H - C | | O - CH 2 - CH 2 - C | | O - C | | O - H The number of double bond/s present in the hydrocarbon is

Step-by-step solution

From the given information: Moles of hydrocarbon = 17 × 10 - 3 136 = 1 . 25 × 10 - 4 Mole of H 2 gas ⇒ 1 × 8 . 40 1000 = n × 0 . 0821 × 273 ⇒ n = 3 . 75 × 10 - 4 Thus, moles of hydrogen used to hydrogenate double bonds: = 3 . 75 × 10 - 4 1 . 25 × 10 - 4 = 3