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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Bohr's Model and Physics of the Atom

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Bohr's Model and Physics of the Atom

Imagine a neutron and an electron bound to each other by...

Imagine a neutron and an electron bound to each other by gravitational force. Assuming Bohr's quantization rule for angular momentum is applicable in this scenario, determine the expression for the energy of the neutron-electron system.

Options

  1. A−2π2G2mnme2n2h2-\dfrac{2 \pi^2 G^2 m_n m_e^2}{n^2 h^2}
  2. B−4π2G2mn2me3n2h2-\dfrac{4 \pi^2 G^2 m_n^2 m_e^3}{n^2 h^2}
  3. C−π2G2mn2me32n2h2-\dfrac{\pi^2 G^2 m_n^2 m_e^3}{2 n^2 h^2}
  4. D−2π2G2mn2me3n2h2-\dfrac{2 \pi^2 G^2 m_n^2 m_e^3}{n^2 h^2}

Correct answer

D. −2π2G2mn2me3n2h2-\dfrac{2 \pi^2 G^2 m_n^2 m_e^3}{n^2 h^2}

Step-by-step solution

The gravitational force provides the necessary centripetal force for the electron to revolve around the neutron.

Gmnmer2=mev2r\dfrac{G m_n m_e}{r^2} = \dfrac{m_e v^2}{r}

v2=Gmnrv^2 = \dfrac{G m_n}{r}

According to Bohr's quantization rule for angular momentum:

mevr=nh2πm_e v r = \dfrac{n h}{2 \pi}

r=nh2πmevr = \dfrac{n h}{2 \pi m_e v}

Substituting rr in the expression for v2v^2:

v2=Gmn2πmevnhv^2 = \dfrac{G m_n 2 \pi m_e v}{n h}

v=2πGmnmenhv = \dfrac{2 \pi G m_n m_e}{n h}

The total energy of the system is the sum of kinetic and potential energy, which is equal to the negative of the kinetic energy:

E=−K=−12mev2E = -K = -\dfrac{1}{2} m_e v^2

E=−12me(2πGmnmenh)2E = -\dfrac{1}{2} m_e \left( \dfrac{2 \pi G m_n m_e}{n h} \right)^2

E=−2π2G2mn2me3n2h2E = -\dfrac{2 \pi^2 G^2 m_n^2 m_e^3}{n^2 h^2}
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