In a circuit, a 50 V battery is connected across points A and B, with the positive terminal at A. An upper branch consists of a 4 F capacitor and an 8 F capacitor in series, with point C situated between them. A lower branch consists of a 3 F capacitor and a 6 F capacitor in series, with point D situated between them. The 4 F and 3 F capacitors are connected to A, while the 8 F and 6 F capacitors are connected to B.

Step-by-step solution

The circuit can be analyzed by finding the potentials at points C and D. Let the potential at B be 0 V , then the potential at A is 50 V . In the upper branch, the 4 F and 8 F capacitors are in series. The equivalent capacitance is: C_ upper = 4 8 4 + 8 = 32 12 = 8 3 F The charge on the upper branch is: Q_ upper = C_ upper V = 8 3 50 = 400 3 C The potential difference across the 4 F capacitor is: V_A - V_C = Q_ upper 4 F = 400/3 4 = 100 3 V In the lower branch, the 3 F and 6 F capacitors are in series. The equivale