Concepts Of Physics MCQ Edition [Volume 2]
- Exam
- Concepts Of Physics MCQ Edition [Volume 2]
- Subject
- Physics
- Chapter
- Capacitors
Concepts Of Physics MCQ Edition [Volume 2] · Physics · Capacitors
A spherical capacitor is formed by two conducting spherical shells...
A spherical capacitor is formed by two conducting spherical shells having radii and . The region between these shells contains a dielectric of dielectric constant up to a radius , as depicted in the figure. Determine the capacitance.


Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
The given spherical capacitor can be considered as a combination of two spherical capacitors connected in series:
1. A capacitor with a dielectric of constant between the radii cC_1 = \dfrac{4\pi\varepsilon_0 K a c}{c - a}C_2cbC_2 = \dfrac{4\pi\varepsilon_0 b c}{b - c}C\dfrac{1}{C} = \dfrac{1}{C_1} + \dfrac{1}{C_2}\dfrac{1}{C} = \dfrac{c - a}{4\pi\varepsilon_0 K a c} + \dfrac{b - c}{4\pi\varepsilon_0 b c}\dfrac{1}{C} = \dfrac{1}{4\pi\varepsilon_0 c} \left( \dfrac{c - a}{K a} + \dfrac{b - c}{b} \right)<br><br>\dfrac{1}{C} = \dfrac{1}{4\pi\varepsilon_0 c} \left( \dfrac{b(c - a) + K a(b - c)}{K a b} \right)
1. A capacitor with a dielectric of constant between the radii cC_1 = \dfrac{4\pi\varepsilon_0 K a c}{c - a}C_2cbC_2 = \dfrac{4\pi\varepsilon_0 b c}{b - c}C\dfrac{1}{C} = \dfrac{1}{C_1} + \dfrac{1}{C_2}\dfrac{1}{C} = \dfrac{c - a}{4\pi\varepsilon_0 K a c} + \dfrac{b - c}{4\pi\varepsilon_0 b c}\dfrac{1}{C} = \dfrac{1}{4\pi\varepsilon_0 c} \left( \dfrac{c - a}{K a} + \dfrac{b - c}{b} \right)<br><br>\dfrac{1}{C} = \dfrac{1}{4\pi\varepsilon_0 c} \left( \dfrac{b(c - a) + K a(b - c)}{K a b} \right)