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Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectric Field and Potential

Two equal charges are situated at a separation of 1.0 m . What must be the magnitude of the charges so that the force between them is equivalent to the weight of a 50 kg person?

Options

  1. A2.3 10⁻⁴ C
  2. B4.6 10⁻⁴ C
  3. C1.2 10⁻⁴ C
  4. D2.3 10⁻⁵ C

Correct answer

A. 2.3 10⁻⁴ C

Step-by-step solution

Weight of the person, W = mg = 50 9.8 = 490 N Electrostatic force between the charges, F = 1 4 ₀ q^2 r^2 Substituting the given values: F = 9 10^9 q^2 1^2 = 9 10^9 q^2 Equating the electrostatic force to the weight: 9 10^9 q^2 = 490 q^2 = 490 9 10^9 = 5.44 10⁻⁸ q = 5.44 10⁻⁸ 2.33 10⁻⁴ C

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