Determine the electric force between two protons separated by a distance of 1 fermi ( 1 fermi = 10^ -15 m ). Protons within a nucleus remain at a separation of this order.

Correct answer: B. 230 N Using Coulomb's law, the electric force between two protons is: F = (1)/(4π _0) (q_1 q_2)/(r^2) Given q_1 = q_2 = 1.6 × 10^ -19 C and r = 10^ -15 m : F = 9 × 10^9 × (1.6 × 10^ -19 )^2 (10^ -15 )^2 F = 9 × 10^9 × 2.56 × 10^ -38 10^ -30 F = 23.04 × 10^1 F = 230.4 N The force is approximately 230 N .

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Electric Field and Potential

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Field and Potential

Determine the electric force between two protons separated by a...

Determine the electric force between two protons separated by a distance of

1

fermi (

1

fermi

= 10^{-15} \text{ m}

). Protons within a nucleus remain at a separation of this order.

Options

A $23 \text{ N}$
B $230 \text{ N}$
C $2.3 \times 10^{-13} \text{ N}$
D $1.44 \times 10^{21} \text{ N}$

Correct answer

B. $230 \text{ N}$

Step-by-step solution

Using Coulomb's law, the electric force between two protons is:

F = \dfrac{1}{4\pi\varepsilon_0} \dfrac{q_1 q_2}{r^2}

Given

q_1 = q_2 = 1.6 \times 10^{-19} \text{ C}

and

r = 10^{-15} \text{ m}

F = \dfrac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{(10^{-15})^2}

F = \dfrac{9 \times 10^9 \times 2.56 \times 10^{-38}}{10^{-30}}

F = 23.04 \times 10^1

F = 230.4 \text{ N}

The force is approximately

230 \text{ N}

Practice Electric Field and Potential on Quantrex Academy →

More from Electric Field and Potential