A 1.0 C charge is positioned at the top of a college building, while another equal charge is located at the top of a house. Assuming the separation between the two charges to be 2.0 km , determine the force they exert

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 2.25 × 10^3 N

According to Coulomb's law, the electrostatic force between two point charges is given by

F = \dfrac{1}{4\pi\epsilon_0} \dfrac{q_1 q_2}{r^2}

Given:

q_1 = 1.0 \text{ C}

q_2 = 1.0 \text{ C}

r = 2.0 \text{ km} = 2.0 \times 10^3 \text{ m}

\dfrac{1}{4\pi\epsilon_0} = 9 \times 10^9 \text{ N m}^2/\text{C}^2

Substituting the values into the formula:

F = \dfrac{9 \times 10^9 \times 1.0 \times 1.0}{(2.0 \times 10^3)^2}

F = \dfrac{9 \times 10^9}{4.0 \times 10^6}

F = 2.25 \times 10^3 \text{ N}

A 1.0 C charge is positioned at the top of a college building,...

Options

Correct answer

Step-by-step solution

More from Electric Field and Potential