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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Heat Transfer

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Heat Transfer

Suspended in an evacuated chamber kept at 300 K , a spherical...

Suspended in an evacuated chamber kept at 300 K300 \text{ K}, a spherical tungsten piece of radius 1.0 cm1.0 \text{ cm} is maintained at a temperature of 1000 K1000 \text{ K} via electrical heating. Determine the rate at which electrical energy must be supplied. The emissivity of tungsten is 0.300.30 and the Stefan constant σ\sigma is 6.0×10−8 W m−2 K−46.0 \times 10^{-8} \text{ W m}^{-2} \text{ K}^{-4}.

Options

  1. A5.6 W5.6 \text{ W}
  2. B11 W11 \text{ W}
  3. C75 W75 \text{ W}
  4. D22 W22 \text{ W}

Correct answer

D. 22 W22 \text{ W}

Step-by-step solution

The rate of electrical energy supplied must equal the net rate of heat loss by radiation to maintain a constant temperature.

According to the Stefan-Boltzmann law, the net rate of heat loss is given by:

P=eσA(T4−T04)P = e \sigma A (T^4 - T_0^4)

Given:

Emissivity, e=0.30e = 0.30

Stefan's constant, σ=6.0×10−8 W m−2 K−4\sigma = 6.0 \times 10^{-8} \text{ W m}^{-2} \text{ K}^{-4}

Radius, r=1.0 cm=10−2 mr = 1.0 \text{ cm} = 10^{-2} \text{ m}

Surface area of the sphere, A=4πr2=4π(10−2)2=4π×10−4 m2A = 4\pi r^2 = 4\pi (10^{-2})^2 = 4\pi \times 10^{-4} \text{ m}^2

Temperature of the sphere, T=1000 KT = 1000 \text{ K}

Temperature of the surroundings, T0=300 KT_0 = 300 \text{ K}

Substituting the values into the formula:

P=0.30×6.0×10−8×4π×10−4×(10004−3004)P = 0.30 \times 6.0 \times 10^{-8} \times 4\pi \times 10^{-4} \times (1000^4 - 300^4)

P=1.8×10−8×4π×10−4×(1012−81×108)P = 1.8 \times 10^{-8} \times 4\pi \times 10^{-4} \times (10^{12} - 81 \times 10^8)

P=7.2π×10−12×1012(1−0.0081)P = 7.2\pi \times 10^{-12} \times 10^{12} (1 - 0.0081)

P=7.2×3.1416×0.9919P = 7.2 \times 3.1416 \times 0.9919

P≈22.4 WP \approx 22.4 \text{ W}

The closest value among the given options is 22 W22 \text{ W}.
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