A gas undergoes a cyclic process ABCA as depicted in the figure. If 2.4 cal of heat is supplied during this process, what is the value of J ?

Step-by-step solution

For a cyclic process, the change in internal energy is zero ( U = 0 ). According to the first law of thermodynamics, the net heat supplied is equal to the net work done: Q = W The net work done W is the area enclosed by the cycle on the P-V diagram. From the given graph, the cycle forms a right-angled triangle with vertices at A(100 kPa , 500 cc ) , B(200 kPa , 500 cc ) , and C(100 kPa , 700 cc ) . The base of the triangle is P = 200 kPa - 100 kPa = 100 10^3 Pa . The height of the triangle is V = 700 cc - 500 cc =