As illustrated in the figure, a substance undergoes the process abc . Determine the value of J if 2625 cal of heat is supplied to the system and the internal energy of the substance increases by 5000 J .

Step-by-step solution

From the given P-V diagram, the process abc consists of an isobaric process ab and an isochoric process bc . The work done during the isobaric process ab is: W_ ab = P(V_b - V_a) = 200 10^3 (0.05 - 0.02) = 6000 J The work done during the isochoric process bc is zero since the volume is constant: W_ bc = 0 Total work done by the system is: W = W_ ab + W_ bc = 6000 J According to the first law of thermodynamics, the total heat supplied in Joules is: Q = U + W = 5000 J + 6000 J = 11000 J Given that the heat supplied i