Two long bar magnets are positioned such that their axes coincide and the north pole of the first magnet is located 2.0 cm away from the south pole of the second. Given that both magnets possess a pole strength of 10 Am , determine the force exerted by one magnet on the other.

Step-by-step solution

Since the magnets are long, the force between them is predominantly due to their adjacent poles. The effect of the farther poles can be neglected. The force between two magnetic poles is given by Coulomb's law for magnetism: F = ₀ 4 m₁ m₂ r^2 Given: Pole strength, m₁ = m₂ = 10 Am Distance between the adjacent poles, r = 2.0 cm = 0.02 m Constant, ₀ 4 = 10⁻⁷ N A ⁻² Substituting the values into the formula: F = 10⁻⁷ 10 10 (0.02)^2 F = 10⁻⁷ 100 4 10⁻⁴ F = 10⁻⁷ 25 10^4 F = 25 10⁻³ N = 0.025 N