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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Permanent Magnets

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Permanent Magnets

Suppose the magnitude of the earth's magnetic field at the magnetic...

Suppose the magnitude of the earth's magnetic field at the magnetic equator is 3.4×10−5 T3.4 \times 10^{-5} \text{ T}. Find its value at the geomagnetic poles of the earth.

Options

  1. A4.8×10−5 T4.8 \times 10^{-5} \text{ T}
  2. B3.4×10−5 T3.4 \times 10^{-5} \text{ T}
  3. C6.8×10−5 T6.8 \times 10^{-5} \text{ T}
  4. D1.7×10−5 T1.7 \times 10^{-5} \text{ T}

Correct answer

C. 6.8×10−5 T6.8 \times 10^{-5} \text{ T}

Step-by-step solution

The earth's magnetic field can be approximated as a magnetic dipole.

The magnitude of the magnetic field of a short dipole at a distance randmagneticlatituder and magnetic latitude\lambdaisgivenby:<br><br>is given by:<br><br>B = \dfrac{\mu_0 M}{4 \pi r^3} \sqrt{1 + 3 \sin^2 \lambda}<br><br>Atthemagneticequator,<br><br>At the magnetic equator,\lambda = 0^{\circ},so, so\sin \lambda = 0.<br><br>.<br><br>B_{eq} = \dfrac{\mu_0 M}{4 \pi r^3} = 3.4 \times 10^{-5} \text{ T}<br><br>Atthegeomagneticpoles,<br><br>At the geomagnetic poles,\lambda = 90^{\circ},so, so\sin \lambda = 1.<br><br>.<br><br>B_{pole} = \dfrac{\mu_0 M}{4 \pi r^3} \sqrt{1 + 3(1)^2} = 2 \left(\dfrac{\mu_0 M}{4 \pi r^3} \right)

Bpole=2BeqB_{pole} = 2 B_{eq}

Bpole=2×3.4×10−5 T=6.8×10−5 TB_{pole} = 2 \times 3.4 \times 10^{-5} \text{ T} = 6.8 \times 10^{-5} \text{ T}
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