Concepts Of Physics MCQ Edition [Volume 2]PhysicsPermanent Magnets
At a location where the angle of dip is 60^ , the earth's magnetic field has a horizontal component of 26 T . Determine the vertical component as well as the magnitude of the magnetic field.
Options
- A52 T , 45 T
- B30 T , 15 T
- C45 T , 52 T
- D15 T , 30 T
Correct answer
C. 45 T , 52 T
Step-by-step solution
Given angle of dip, = 60^ Horizontal component of earth's magnetic field, B_H = 26 T The vertical component B_V is given by: B_V = B_H B_V = 26 60^ = 26 3 26 1.732 = 45.03 T 45 T The magnitude of the earth's magnetic field B is given by: B = B_H B = 26 60^ = 26 1/2 = 52 T Thus, the vertical component is 45 T and the magnitude of the magnetic field is 52 T .