A metal has a work function of 2.5 × 10^ -19 J . Determine the threshold frequency for photoelectric emission.

Correct answer: C. 3.8 × 10^ 14 Hz The work function of a metal is related to its threshold frequency by the equation = h _0 , where h is Planck's constant and _0 is the threshold frequency. Substituting the given values: _0 = ( )/(h) _0 = 2.5 × 10^ -19 6.63 × 10^ -34 _0 3.77 × 10^ 14 Hz Rounding to one decimal place, _0 3.8 × 10^ 14 Hz

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Photoelectric Effect and Wave–Particle Duality

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Photoelectric Effect and Wave–Particle Duality

A metal has a work function of 2.5 × 10^ -19 J . Determine the...

A metal has a work function of

2.5 \times 10^{-19} \text{ J}

. Determine the threshold frequency for photoelectric emission.

Options

A $2.5 \times 10^{14} \text{ Hz}$
B $5.2 \times 10^{14} \text{ Hz}$
C $3.8 \times 10^{14} \text{ Hz}$
D $1.9 \times 10^{14} \text{ Hz}$

Correct answer

C. $3.8 \times 10^{14} \text{ Hz}$

Step-by-step solution

The work function of a metal is related to its threshold frequency by the equation

\Phi = h \nu_0

, where

h

is Planck's constant and

\nu_0

is the threshold frequency.

Substituting the given values:

\nu_0 = \dfrac{\Phi}{h}

\nu_0 = \dfrac{2.5 \times 10^{-19}}{6.63 \times 10^{-34}}

\nu_0 \approx 3.77 \times 10^{14} \text{ Hz}

Rounding to one decimal place,

\nu_0 \approx 3.8 \times 10^{14} \text{ Hz}

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