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Concepts Of Physics MCQ Edition [Volume 2]PhysicsPhotoelectric Effect and Wave–Particle Duality

A photographic film is coated with a layer of silver bromide. When light strikes this film, the silver bromide molecules dissociate, and the film records the light. A minimum of 0.6 eV is required to dissociate a silver bromide molecule. Determine the maximum wavelength of light that can be recorded by the film.

Options

  1. A4140 nm
  2. B2070 nm
  3. C3105 nm
  4. D1035 nm

Correct answer

B. 2070 nm

Step-by-step solution

The minimum energy required to dissociate a silver bromide molecule is given as E = 0.6 eV . The energy of a photon is related to its wavelength by the equation E = hc . For maximum wavelength, the energy of the photon must be equal to the minimum dissociation energy. _ max = hc E_ min Substituting hc = 1242 eV nm and E_ min = 0.6 eV : _ max = 1242 0.6 nm _ max = 2070 nm

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