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Concepts Of Physics MCQ Edition [Volume 2]PhysicsPhotoelectric Effect and Wave–Particle Duality

During a photoelectric experiment, the collector plate is maintained at 2.0 V relative to a copper emitter plate ( = 4.5 eV ). A monochromatic light source of wavelength 200 nm illuminates the emitter. Determine the minimum and maximum kinetic energy of the photoelectrons upon reaching the collector.

Options

  1. A2.0 eV and 8.2 eV
  2. B4.5 eV and 6.2 eV
  3. C0 eV and 1.7 eV
  4. D2.0 eV and 3.7 eV

Correct answer

D. 2.0 eV and 3.7 eV

Step-by-step solution

The energy of the incident photon is given by: E = hc = 1240 eV nm 200 nm = 6.2 eV According to Einstein's photoelectric equation, the maximum kinetic energy of the emitted photoelectrons is: K_ = E - = 6.2 eV - 4.5 eV = 1.7 eV The minimum kinetic energy of the emitted photoelectrons is: K_ = 0 eV The collector plate is maintained at a positive potential of 2.0 V relative to the emitter. Therefore, the electrons are accelerated and gain an additional kinetic energy of 2.0 eV . The maximum kinetic energy of the phot

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