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Concepts Of Physics MCQ Edition [Volume 2]PhysicsPhotoelectric Effect and Wave–Particle Duality

A metal plate with a work function of 2.2 eV is illuminated by a light beam having a wavelength of 400 nm . A particular electron absorbs a photon and undergoes two collisions before emerging from the metal. Assuming that 10 % of the extra energy is lost to the metal during each collision, determine the kinetic energy of this electron as it exits the metal.

Options

  1. A0.31 eV
  2. B0.59 eV
  3. C0.73 eV
  4. D0.90 eV

Correct answer

A. 0.31 eV

Step-by-step solution

Energy of the incident photon is given by: E = hc Using hc = 1240 eV nm and = 400 nm : E = 1240 400 = 3.1 eV The electron absorbs this photon, so its extra energy inside the metal is 3.1 eV . During each collision, the electron loses 10 % of its extra energy to the metal, meaning it retains 90 % of its energy after each collision. Energy remaining after two collisions is: E' = 3.1 (0.9)^2 = 3.1 0.81 = 2.511 eV To emerge from the metal, the electron must overcome the work function = 2.2 eV . The kinetic energy of th

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