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Concepts Of Physics MCQ Edition [Volume 2]PhysicsSemiconductors and Semiconductor Devices

A potential barrier of 250 meV exists across a p - n junction. A hole possessing a kinetic energy of 300 meV approaches the junction from the p -side. Determine the kinetic energy of the hole after it crosses the junction.

Options

  1. A550 meV
  2. B300 meV
  3. C250 meV
  4. D50 meV

Correct answer

D. 50 meV

Step-by-step solution

The potential barrier across a p - n junction opposes the motion of majority charge carriers. The electric field in the depletion region is directed from the n -side to the p -side. When a hole (which acts as a positive charge) moves from the p -side to the n -side, it moves against the electric field and loses kinetic energy equal to the potential barrier energy. By conservation of energy, the final kinetic energy K_ f of the hole after crossing the junction is given by: K_ f = K_ i - e V₀ where K_ i is the initia

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