An amplifier circuit employs a transistor in common-emitter mode, with a load resistor of 2 k connected in the collector branch. The transistor has a current gain β = 50 and an input resistance of 0.50 k . When the

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Quantrex Academy · Accepted Answer

Correct answer: B. 5.0 V

The given parameters are:

Current gain,

\beta = 50

Load resistance,

R_L = 2 \text{ k}\Omega = 2 \times 10^3 \Omega

Change in input current,

\Delta I_B = 50 \mu\text{A} = 50 \times 10^{-6} \text{ A}

The change in output current (collector current) is given by:

\Delta I_C = \beta \Delta I_B

\Delta I_C = 50 \times 50 \times 10^{-6} \text{ A} = 2.5 \times 10^{-3} \text{ A}

The change in output voltage across the load resistor is:

\Delta V_{out} = \Delta I_C \times R_L

\Delta V_{out} = 2.5 \times 10^{-3} \times 2 \times 10^3 \text{ V} = 5.0 \text{ V}

An amplifier circuit employs a transistor in common-emitter mode,...

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