If the base current of a transistor is altered from 30 to 80 , its collector current shifts from 1.0 mA to 3.5 mA . Determine the current gain β .

Correct answer: B. 50 The change in base current is given by Δ I_B = 80 - 30 = 50 . The change in collector current is given by Δ I_C = 3.5 mA - 1.0 mA = 2.5 mA = 2500 . The AC current gain of the transistor is defined as β = (Δ I_C)/(Δ I_B) . Substituting the values, we get β = 2500 50 = 50 .

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Semiconductors and Semiconductor Devices

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Semiconductors and Semiconductor Devices

If the base current of a transistor is altered from 30 to 80 , its...

If the base current of a transistor is altered from

30 \mu\text{A}

80 \mu\text{A}

, its collector current shifts from

1.0 \text{ mA}

3.5 \text{ mA}

. Determine the current gain

\beta

Options

A $20$
B $50$
C $500$
D $0.05$

Correct answer

B. $50$

Step-by-step solution

The change in base current is given by

\Delta I_B = 80 \mu\text{A} - 30 \mu\text{A} = 50 \mu\text{A}

.

The change in collector current is given by

\Delta I_C = 3.5 \text{ mA} - 1.0 \text{ mA} = 2.5 \text{ mA} = 2500 \mu\text{A}

.

The AC current gain of the transistor is defined as

\beta = \dfrac{\Delta I_C}{\Delta I_B}

.

Substituting the values, we get

\beta = \dfrac{2500 \mu\text{A}}{50 \mu\text{A}} = 50

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