Consider the expression X = A BC + B CA + C AB . Find the value of X if A = B = C = 1 .

Correct answer: A. 0 Given the Boolean expression X = A BC + A B C + AB C . Substituting the values A = 1 , B = 1 , and C = 1 , we get the complements as A = 0 , B = 0 , and C = 0 . Substituting these into the expression: X = (0)(1)(1) + (1)(0)(1) + (1)(1)(0) X = 0 + 0 + 0 = 0 Thus, the value of X is 0 .

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Semiconductors and Semiconductor Devices

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Semiconductors and Semiconductor Devices

Consider the expression X = A BC + B CA + C AB . Find the value of...

Consider the expression

X = \overline{A}BC + \overline{B}CA + \overline{C}AB

. Find the value of

X

A = B = C = 1

Options

A $0$
B $1$
C $-1$
D $2$

Correct answer

A. $0$

Step-by-step solution

Given the Boolean expression

X = \overline{A}BC + A\overline{B}C + AB\overline{C}

.

Substituting the values

A = 1

B = 1

, and

C = 1

, we get the complements as

\overline{A} = 0

\overline{B} = 0

, and

\overline{C} = 0

.

Substituting these into the expression:

X = (0)(1)(1) + (1)(0)(1) + (1)(1)(0)

X = 0 + 0 + 0 = 0

Thus, the value of

X

0

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