Consider the expression X = A BC + B CA + C AB . Find the value of X if A = 1 , B = 0 , and C = 1 .

Correct answer: B. 1 Given A = 1 , B = 0 , C = 1 . The complements are A = 0 , B = 1 , C = 0 . Substituting these values into the given Boolean expression X = A BC + B CA + C AB : X = (0 · 0 · 1) + (1 · 1 · 1) + (0 · 1 · 0) X = 0 + 1 + 0 = 1

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Semiconductors and Semiconductor Devices

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Semiconductors and Semiconductor Devices

Consider the expression X = A BC + B CA + C AB . Find the value of...

Consider the expression

X = \overline{A}BC + \overline{B}CA + \overline{C}AB

. Find the value of

X

A = 1

B = 0

, and

C = 1

Options

A $-1$
B $1$
C $2$
D $0$

Correct answer

B. $1$

Step-by-step solution

Given

A = 1

B = 0

C = 1

.

The complements are

\overline{A} = 0

\overline{B} = 1

\overline{C} = 0

.

Substituting these values into the given Boolean expression

X = \overline{A}BC + \overline{B}CA + \overline{C}AB

X = (0 \cdot 0 \cdot 1) + (1 \cdot 1 \cdot 1) + (0 \cdot 1 \cdot 0)

X = 0 + 1 + 0 = 1

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