An ideal gas ( = 1.67 ) is taken through the process abc shown in the figure. The temperature at the point a is 300 K . Calculate the temperatures at b and c .

Step-by-step solution

From the given graph, the pressure and volume at points a , b , and c are: P_a = 100 kPa , V_a = 100 cm ^3 P_b = 200 kPa , V_b = 100 cm ^3 P_c = 200 kPa , V_c = 150 cm ^3 Using the ideal gas equation, PV T = constant . For the isochoric process a b ( V = constant ): P_a T_a = P_b T_b T_b = T_a P_b P_a = 300 200 100 = 600 K For the isobaric process b c ( P = constant ): V_b T_b = V_c T_c T_c = T_b V_c V_b = 600 150 100 = 900 K The temperatures at b and c are 600 K and 900 K respectively.