An ideal gas ( = 1.67 ) is taken through the process abc shown in the figure. The temperature at the point a is 300 K . Calculate the amount of heat supplied in the path ab and in the path bc .

Step-by-step solution

From the given graph: Path a b is an isochoric process (constant volume) where V = 100 cm ^3 = 10⁻⁴ m ^3 . The pressure changes from P_a = 100 kPa = 10^5 Pa to P_b = 200 kPa = 2 10^5 Pa . The heat supplied at constant volume is given by: Q_ ab = nC_V T = V P - 1 Substituting the values: Q_ ab = 10⁻⁴ (2 10^5 - 10^5) 1.67 - 1 Q_ ab = 10⁻⁴ 10^5 0.67 = 10 0.67 14.9 J Path b c is an isobaric process (constant pressure) where P = 200 kPa = 2 10^5 Pa . The volume changes from V_b = 100 cm ^3 = 10⁻⁴ m ^3 to V_c = 150 cm ^3