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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Specific Heat Capacities of Gases

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Specific Heat Capacities of Gases

Occupying 100 cc , an ideal gas is initially at a pressure of 2.5 ×...

Occupying 100 cc100 \text{ cc}, an ideal gas is initially at a pressure of 2.5×105 Pa2.5 \times 10^5 \text{ Pa} and a temperature of 300 K300 \text{ K}. It is adiabatically compressed to half its original volume. Determine the final temperature of the gas. Take γ=1.5\gamma = 1.5.

Options

  1. A600 K600 \text{ K}
  2. B424 K424 \text{ K}
  3. C150 K150 \text{ K}
  4. D848 K848 \text{ K}

Correct answer

B. 424 K424 \text{ K}

Step-by-step solution

For an adiabatic process, the relation between temperature and volume is given by

T1V1γ−1=T2V2γ−1T_1 V_1^{\gamma - 1} = T_2 V_2^{\gamma - 1}

Given T1=300 KT_1 = 300 \text{ K}, V1=VV_1 = V, V2=V2V_2 = \dfrac{V}{2}, and γ=1.5\gamma = 1.5.

Substituting the values in the equation:

300×V1.5−1=T2×(V2)1.5−1300 \times V^{1.5 - 1} = T_2 \times \left(\dfrac{V}{2}\right)^{1.5 - 1}

300×V0.5=T2×V0.520.5300 \times V^{0.5} = T_2 \times \dfrac{V^{0.5}}{2^{0.5}}

T2=300×2T_2 = 300 \times \sqrt{2}

T2=300×1.414=424.2 KT_2 = 300 \times 1.414 = 424.2 \text{ K}

The final temperature of the gas is approximately 424 K424 \text{ K}.
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